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767:, Maurice (1976). "Deux propriétés décidables des suites récurrentes linéaires"...
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fonts they are discernible from the digits "1" and "0". Collins, G. E.;
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564:, Maude (14 August 2022). "Louis Grillot, ancien sénateur de CÎte-d'Or et...
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12 August 2022, at the age of 90. "GRILLOT Louis". Senate (in French).
505:, M. (2012). Mathematics for computer algebra. Springer Science & Business...
439:, Maurice (2014). The Problem of Catalan. Springer. OCLC 893117743. MetsÀnkylÀ...
281:, M. (2012). Mathematics for computer algebra. Springer Science & Business...
11:
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shows that if n > 30, then U n {\displaystyle U_{n}} has a primitive prime...
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precursors », Blood, 1979 oct;54(4), p. 940-5 Romeo PH, Prandini MH, Joulin V,
373:, and S. Siksek proved that 8 and 144 are the only such non-trivial perfect...
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Profile Books. p. 124. ISBN 978-1-84765-351-2. Bilu, Yuri F.; Bugeaud, Yann;
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b + b2 +...+ bq-1 with b, n, t > 1 and q > 2. Yann
Bugeaud and Maurice
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Tijdeman imply that the number of solutions in each case is finite. Bugeaud,
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bound can refer to a bound on coefficients of factor polynomials, see Landau-
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bound) is one of a family of inequalities concerning a univariate integer...
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711:(2012) instead cite a 1934 paper of Skolem for this result. Berstel, Jean;
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French merde. smerdare: to shame, to take down a peg or two. mignotta (pl.
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and algebraic computation (Vol. 4). Springer
Science & Business Media.
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separation bound is sep ⥠( p ) > 3 | Î ( p ) | n ( n + 1 ) / 2 ( â p...
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and algebraic computation (Vol. 4). Springer
Science & Business Media.
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V, Prenant M, Vainchenker W, Marguerie G, Uzan G., « Megakaryocytic and...
619:(1): 33â53. doi:10.4064/aa-56-1-33-53. ISSNÂ 0065-1036. Belaga, Edward G.;
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bound. Let n be odd, square-free, and greater than 3. Then: 4 Ί n ( z )...
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finite number of perfect power
Fibonacci numbers. In 2006, Y. Bugeaud, M.
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and Siksek solved equations of this type with A = 1 and 1 †D †100. In...
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1â9. doi:10.1145/3531130.3533328. ISBNÂ 978-1-4503-9351-5. Berstel, Jean;
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conjecture that only three perfect powers are
Brazilian repunits. They...
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and AsmuthâBloom schemes, which are explained below. As said before, the
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who, however, is no abstraction, but an honest baker with a wife called
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the original coefficients. This is not too far from the general Landau-
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bounds for root separation that are independent from the discriminant.
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In the case D is negative, a deep result of Bilu, Hanrot, Voutier and
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